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# Integrating factor of $\large\frac{dy}{dx}+\frac{1}{x\log x}$$.y=\large\frac{2}{x^{2}} is $\begin{array}{1 1}(1)e^{x}&(2)\log x\\(3)\frac{1}{x}&(4)e^{-x}\end{array}$ Can you answer this question? ## 1 Answer 0 votes \large\frac{dy}{dx}+ \frac{1}{x \log x }$$y =\large\frac{2}{x^2}$
$P= \large\frac{1}{x \log x }$