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# $y=cx-c^{2}$ is the general solution of the differential equation

$\begin{array}{1 1}(1)(y')^{2}-xy'+y=0&(2)y''=0\\(3)y'=c&(4)(y')^{2}+xy'+y=0\end{array}$

Can you answer this question?

$y= cx-c^2$-----(1)
$y'=c$
$=> y= xy'- (y')^2$
$(y')^2 -xy^1 +y=0$
Hence 1 is the correct answer.
answered May 21, 2014 by