Browse Questions

# The degree of the differential equation $\Large\sqrt{1+\left(\frac{dy}{dx}\right)^{1/3}}=\frac{d^{2}y}{dx^{2}}$

$\begin{array}{1 1}(1)1&(2)2\\(3)3&(4)6\end{array}$

$\sqrt {1+(\large\frac{dy}{dx})^{1/3} } =\frac{d^2 y}{dx^2}$
squaring $1+ (\large\frac{dy}{dx} )^{1/3}=( \frac{d^2 y}{dx^2})^2$