Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The degree of the differential equation $\;\Large c=\frac{\left[1+\left(\frac{dy}{dx}\right)^{3}\right]^{2/3}}{\frac{d^{3}y}{dx^{3}}}$ where $c$ is a constant

\[\begin{array}{1 1}(1)1&(2)3\\(3)-2&(4)2\end{array}\]

Can you answer this question?

1 Answer

0 votes
$C =\large\frac{\left[1+\left(\frac{dy}{dx}\right)^{3}\right]^{2/3}}{\frac{d^{3}y}{dx^{3}}}$
$C \large\frac{d^3y}{dx^3}=\bigg[1+\bigg(\frac{dy}{dx}\bigg)^{3}\bigg]^{2/3}$
Raising both sides to the powder 3
$C^3 \bigg(\large\frac{d^3y}{dx^3} \bigg)^3= \bigg[1+ \bigg( \large\frac{dy}{dx} \bigg)^3 \bigg]^2$
Order =3
degree =3
Hence 2 is the correct answer
answered May 22, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App