# $X$ is a discrete random variable which takes the values $0, 1, 2$ and $P(X=0)=\large\frac{144}{169},$$P(X=1)=\large\frac{1}{169} then the value of P(X=2) is $\begin{array}{1 1}(1)\frac{145}{169}&(2)\frac{24}{169}\\(3)\frac{2}{169}&(4)\frac{143}{169}\end{array}$ ## 1 Answer Given P(X=0)+P(X=1)+P(X=2)=1 \large\frac{144}{169} +\frac{1}{169}$$+P(X=2) =1$
$P(X=2)=1- \large\frac{145}{169}$
$\qquad= \large\frac{169-145}{169}$
$P(X=1)=\large\frac{24}{169}$
Hence 2 is the correct answer.