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Recent questions tagged continuity
Questions
If $ f(x) = \left\{ \begin{array}{l l} \large\frac{x^3+x^2-16x+20}{(x-2)^2} & \quad when \quad x \neq 3 \\ k & \quad when \quad x = 2 \end{array} \right. $ and $f(x)$ is continuous at $x=3$ find the value of k.
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
asked
Apr 22, 2014
by
meena.p
1
answer
If $ f(x) = \left\{ \begin{array}{l l} \large\frac{|x+2|}{\tan^{-1} (x+2)} & \quad x \neq -2 \\ 2 & \quad x=-2 \end{array} \right. $ then $f(x) $ is
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
asked
Apr 22, 2014
by
meena.p
1
answer
If the function $ f(x) = \left\{ \begin{array}{l l} 3ax+b & \quad for \quad x > 1 \\ 11 & \quad for \quad x = 1 \\ 5ax-2b & \quad for \quad x < 1 \end{array} \right. $ is continuous at $x=1$.find the values of a and b .
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
asked
Apr 22, 2014
by
meena.p
1
answer
Find the values of K. So that the function $ f(x) = \left\{ \begin{array}{l l} \large\frac{k \cos x}{\pi -2x} & \quad if \quad x \neq \large\frac{\pi}{2} \\ 3 & \quad if \quad x =\large\frac{\pi}{2} \end{array} \right. $ is continuous at $x =\large\frac{\pi}{2}$ .
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
asked
Apr 22, 2014
by
meena.p
1
answer
Determine the value of K so that the function. $ f(x) = \left\{ \begin{array}{l l} Kx^2 & \quad if \quad x \leq 2 \\ 3 & \quad if \quad x > 2 \end{array} \right. $ is continuous .
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
asked
Apr 22, 2014
by
meena.p
1
answer
At the point $x=1$ the function $f(x)=\left\{\begin{array}{1 1}x^3-1&1 < x < \infty\\x-1&-\infty < x \leq 1\end{array}\right.$ is
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q178
asked
Jan 6, 2014
by
sreemathi.v
1
answer
$f(x)=\left\{\begin{array}{1 1}\large\frac{1-\cos 4x}{x^2}&x < 0\\a&x=0\\\large\frac{\sqrt x}{\sqrt{[16+\sqrt x]-4}}&x > 0\end{array}\right.$If the function be continuous at $x=0$ then $a=$
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q177
asked
Jan 6, 2014
by
sreemathi.v
1
answer
The function $f(x)=\left\{\begin{array}{1 1}x+a\sqrt 2\sin x&0\leq x < \large\frac{\pi}{4}\\2x\cot x+b&\large\frac{\pi}{4}\normalsize \leq x < \frac{\pi}{2}\\a\cos 2x-b\sin x&\large\frac{\pi}{2}\normalsize < x \leq \pi\end{array}\right.$ is continuous for $0 \leq x \leq \pi$ then a,b are
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q176
asked
Jan 6, 2014
by
sreemathi.v
1
answer
The function $f(x)=\left\{\begin{array}{1 1}\large\frac{x^2}{a}&0\leq x <1\\a&1\leq x < \sqrt 2\\\large\frac{2b^2-4b}{x^2}&\sqrt 2\leq x < \infty\end{array}\right.$ is continuous for $0\leq x < \infty$ then the most suitable values of a and b are
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q167
asked
Jan 4, 2014
by
sreemathi.v
1
answer
The value of $\lim\limits_{x\to 0}\large\frac{\sqrt{\Large\frac{1}{2}\normalsize (1-\cos 2x)}}{x}$
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q165
asked
Jan 4, 2014
by
sreemathi.v
1
answer
If $f(x)=\large\frac{x}{2}$$-1$, then on the interval $[0,\pi]$
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q164
asked
Jan 4, 2014
by
sreemathi.v
1
answer
Consider the function $f(x)=|x-2|+|x-5|\;x\in R$.
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q159
asked
Jan 3, 2014
by
sreemathi.v
1
answer
If $f:R\to R$ is a function defined by $f(x)=[x]\cos\big(\large\frac{2x-1}{2}\big)$$\pi$ where [x] denotes the greatest integer function then f is
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q158
asked
Jan 3, 2014
by
sreemathi.v
1
answer
Let $f(x)=[x]\sin\bigg[\large\frac{\pi}{[x+1]}\bigg]$ where [.] denotes the greatest integer function. The domain of $f$ is and the point of discontinuity of $f$ in the domain are
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q157
asked
Jan 3, 2014
by
sreemathi.v
1
answer
The function $f(x)=[x]^2-[x^2]$ where $[x]$ is the greatest integer less than or equal to x, is discontinuous at
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q153
asked
Jan 3, 2014
by
sreemathi.v
1
answer
The function $f:R\{0\}\rightarrow R$ given by $f(x)=\large\frac{1}{x}-\frac{2}{e^{2x}-1}$ can be made continuous at $x=0$ by defining f(0) as
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q152
asked
Jan 3, 2014
by
sreemathi.v
1
answer
$f$ is defined in [-5,5] as $f(x)=\left\{\begin{array}{1 1}x&if\;x\;is\;rational\\-x&if\;x\;is\;irrational\end{array}\right.$. Then
jeemain
math
ch5
continuity-and-differentiability
continuity
difficult
q151
asked
Jan 3, 2014
by
sreemathi.v
1
answer
The function $f(x)=[x]\cos\big[\large\frac{2x-1}{2}\big]$$\pi$ where [.] denotes the greatest integer function, is discontinuous at
jeemain
math
ch13
continuity-and-differentiability
continuity
difficult
q146
asked
Jan 3, 2014
by
sreemathi.v
1
answer
In order that the function $f(x)=(x+1)^{\large\cot x}$ is continuous at $x=0$. f(0) must be defined as
jeemain
math
ch5
continuity-and-differentiability
continuity
medium
q128
asked
Jan 2, 2014
by
sreemathi.v
1
answer
If $f(x)=\left\{\begin{array}{1 1}\large\frac{1-\cos\lambda x}{x\sin x}&x\neq 0\\\large\frac{1}{2}&x=0\end{array}\right.$ is continuous at $x=0$ then $\lambda$ is
jeemain
math
ch5
continuity-and-differentiability
continuity
medium
q122
asked
Jan 2, 2014
by
sreemathi.v
1
answer
Find the value of p for which the function $f(x)=\left\{\begin{array}{ 1 1}\large\frac{(4^x-1)^3}{\sin\big(x/p\big)\log \big(1+\Large\frac{x^2}{3}\big)}&x\neq 0\\12(\log 4)^3&x=0\end{array}\right.$ is continuous at $x=0$
jeemain
math
ch5
continuity-and-differentiability
continuity
medium
q121
asked
Dec 31, 2013
by
sreemathi.v
1
answer
Find the points of discontinuity of $y=\large\frac{1}{u^2+u-2}$ where $u=\large\frac{1}{x-1}$
jeemain
math
ch5
continuity-and-differentiability
continuity
medium
q120
asked
Dec 31, 2013
by
sreemathi.v
1
answer
The values of $p$ and $q$ for which the function $f(x)=\left\{\begin{array}{1 1}\large\frac{\sin(p+1)x+\sin x}{x} & x < 0 \\ q & x=0 \\ \large\frac{\sqrt{x+x^2}-\sqrt x}{x^3/2} & x > 0 \end{array}\right.$ is continuous for all $x\;in\;R$ are
jeemain
math
ch5
continuity-and-differentiability
continuity
medium
q114
asked
Dec 31, 2013
by
sreemathi.v
1
answer
Let [.] denote the greatest integer function and $f(x)=[\tan^2x]$ then
jeemain
math
ch5
continuity-and-differentiability
continuity
medium
q105
asked
Dec 31, 2013
by
sreemathi.v
1
answer
Let $f(x)$ be a continuous function defined for $1\leq x\leq 3$. If $f(x)$ takes rational value for all $x$ and $f(2) = 10$ then $f(1.5)$ =
jeemain
math
ch5
continuity-and-differentiability
continuity
medium
q100
asked
Dec 31, 2013
by
sreemathi.v
1
answer
Let $f(x)=\left\{\begin{array}{1 1}\big[\tan(\large\frac{\pi}{4}\normalsize +x)\big]^{\large\frac{1}{x}}&x\neq 0\\k&x=0\end{array}\right.$.For what value of k,$f(x)$ is continuous at $x=0$
jeemain
math
ch5
continuity-and-differentiability
continuity
easy
q97
asked
Dec 30, 2013
by
sreemathi.v
1
answer
If $f(x)=\large\frac{1}{1-x}$,find the points of discontinuity of the composite function $y=f(f(f(x)))$
jeemain
math
ch5
continuity-and-differentiability
continuity
easy
q96
asked
Dec 30, 2013
by
sreemathi.v
1
answer
If $f(x)=\large\frac{x^2-10x+25}{x^2-7x+10}$ for $x\neq 5$ and $f$ is continuous at $x=5$ then $f(5)=$
jeemain
math
ch5
continuity-and-differentiability
continuity
easy
q89
asked
Dec 30, 2013
by
sreemathi.v
1
answer
$f(x)=\left\{\begin{array}{1 1}\large\frac{x^5-32}{x-2}&x\neq 2\\k&x=2\end{array}\right.$ is continuous at $x=2$ then $k=$
jeemain
math
ch5
continuity-and-differentiability
continuity
easy
q86
asked
Dec 30, 2013
by
sreemathi.v
1
answer
If $f$ is continuous on $[0,1]$ and $f\big(\large\frac{1}{3}\big)$$=1$ then $\lim\limits_{n\to \infty}f(\large\frac{n}{\sqrt{9n^2+1}}\big)$=
jeemain
math
ch5
continuity-and-differentiability
continuity
easy
q84
asked
Dec 30, 2013
by
sreemathi.v
1
answer
If $f(x)=\large\frac{1-\tan x}{4x-\pi}\qquad $$x\neq \large\frac{\pi}{4}$,$x \in [0,\large\frac{\pi}{2}]$ and f(x) is continuous in $[0,\large\frac{\pi}{2}]$ then $f(\large\frac{\pi}{4})$
jeemain
math
class12
ch5
continuity-and-differentiability
continuity
easy
q70
asked
Dec 24, 2013
by
sreemathi.v
1
answer
$f(x)=\large\frac{\log(1+ax)-\log(1-bx)}{x}$ is not defined at $x=0$ .The value which should be assigned to f at $x=0$.So that it is continuous at $x=0$ is
jeemain
math
class11
ch5
continuity and dfferentiability
continuity
easy
q63
asked
Dec 24, 2013
by
sreemathi.v
1
answer
The value of $f(0)$ so that the function $f(x)=\large\frac{2x-\sin^{-1}x}{2x+\tan^{-1}x}$ is continuous at each point on its domain is
jeemain
math
class12
ch5
continuity-and-differentiability
continuity
easy
q58
asked
Dec 24, 2013
by
sreemathi.v
1
answer
If the function $f(x)=\left\{\begin{array}{1 1}\large\frac{x^2-(A+2)x+A}{x-2}&x\neq 2\\2&x=2\end{array}\right.$ is continuous at $x=2$ then
jeemain
math
class12
ch5
continuity-and-differentiability
continuity
easy
q57
asked
Dec 24, 2013
by
sreemathi.v
1
answer
If $f(x)=(x+1)^{\cot x}$ is continuous at $x=0$ then $f(0)$ is
jeemain
math
clas12
continuity-and-differentiability
continuity
easy
q47
asked
Dec 24, 2013
by
sreemathi.v
2
answers
The function $f(x)=\sin^{-1}(\cos x)$ is
jeemain
math
class12
ch5
continuity-and-differentiability
continuity
easy
q43
asked
Dec 23, 2013
by
sreemathi.v
1
answer
$\lim\limits_{x\to 0}\large\frac{\sqrt{1-\cos 2x}}{\sqrt{2x}}$ is
jeemain
math
class12
ch5
continuity-and-differentiability
continuity
easy
q16
asked
Dec 20, 2013
by
sreemathi.v
1
answer
A discontinuous function $y=f(x)$ satisfying $x^2+y^2=4$ is given by $f(x)$=_________
jeemain
math
class12
ch5
continuity-and-differentiability
continuity
easy
q3
asked
Dec 20, 2013
by
sreemathi.v
1
answer
Let $f(x)=\left\{\small\begin{array}{1 1} \large\frac{(x^3+x^2-16x+20)}{(x-2)^2}&if\;x\neq 2\\K&if\;x=2\end{array}\right.$. If $f(x)$ is continuous for all $x$ then $K$ =
jeemain
math
class
12
ch5
continuity-and-differentiability
continuity
easy
q2
asked
Dec 20, 2013
by
sreemathi.v
1
answer
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