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Answers posted by apurvtarkas22
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A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of $8\;rad-s^{-2}$ is produced in it due to the torque. Then moment of inertia of the wheel is :
answered
Oct 31, 2018
We know that Torque=r×f=I alpha Given., R=0.4m ,alpha(angular acceleration)=8 radian/s^2 ,M=4kg So..
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