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Answers posted by naveenmeena20000
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Given $E^o_{\frac{Cr^3+}{Cr}}=-0.72V$,$E^o_{\frac{Fe^2+}{Fe}}=-0.42V$.The potential for the cell $Cr|Cr^{3+}(0.1 M)| |Fe^{2+}(0.01 M)|Fe$ is
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Jun 20, 2019
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