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Answers posted by priyanka.clay6

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answered May 15, 2020
$\frac{x-1}{2} = \frac{y+1}{3} = \frac{z-1}{4}$ $ \frac{x-3}{1} = \frac{y-k}{2} = \frac{z}{1}$Let ...
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answered May 15, 2020
https://clay6.com/mpaimg/1856_a.jpgGiven ratio is $3:2$Coordinates of $C$ is $\large\frac{3(2)+2(1)}...
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answered May 15, 2020
$ 3 \sin P + 4 \cos Q = 6 $ $4 \sin Q + 3 \cos P = 1$squaring and adding we get,$\sin (P+Q)=\frac{1...
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answered May 7, 2020
$h=\large\frac{1}{2}$$gt^2$$\large\frac{h_1}{h_2}=\frac{\Large\frac{1}{2}gt^2}{\Large\frac{1}{2}g(\l...
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answered May 7, 2020
$x=at^2-bt^3$$v=\large\frac{dx}{dt}$$=2at-3bt^2$$a=\large\frac{dv}{dt}$$=2a-6bt=0$$\implies t=\large...
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answered May 7, 2020
$dS=kt \;dt$$S=\large\frac{1}{2}$$kt^2$$\quad= \large\frac{1}{2}$$ \times 2 \times 3 \times 3\;m$ $...
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answered May 7, 2020
$S_N = u+\large\frac{a}{2} $$(2n-1)$$S_5= u+ \large\frac{9a}{2}$-------(1)$S_8= u+ \large\frac{15a}{...
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answered May 7, 2020
Total number of gifts $=150$Let the number of $ \$ 50$ is xThen the number of gifts of $\$100$ is $...
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answered May 7, 2020
Total length of the train = $850+150 = 1000\; m$$\;\;\;V = \large\frac{displacement }{time}$$\theref...
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answered May 2, 2020
$100 \times a_{100} = 50 \times a_{50}$$100 (a + 99d) = 50 (a+49 d)$$\implies 2a+198 d = a +49 d$$\i...
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answered May 2, 2020
$(\sqrt{3} + 1)^{2n} - (\sqrt{3} - 1)^{2n}$$= 2[^{2n}C_1 (\sqrt{3})^{2n-1} + 2nC_3(\sqrt{3})^{2n-3} ...
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answered May 2, 2020
$\begin{align*} \int \large \frac{5 \tan x}{\tan x - 2} dx \end{align*}$$=\displaystyle \int \large\...
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answered May 2, 2020
Let $p=$ I become a teacher$\qquad q =$ I will open a school$\sim (p \to q) = p \wedge \sim q$(ie)...
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answered May 2, 2020
Let $e^{\sin x}= a$$\qquad a - a^{-1} -4 =0$$\implies a - \frac{1}{a} -4 = 0$$\implies a^2 - 4a -1 =...
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answered Apr 24, 2020
$\begin{bmatrix} (x^{1/3}+1) -(\frac{\sqrt{x}+1}{\sqrt{x}})^{10}\end{bmatrix}$$\qquad = (x^{1/3}-x^{...
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answered Apr 24, 2020
Given : $2x+y+2z-8=0---(1)$$\qquad 2x+y+2z+\frac{5}{2}=0---(2)$Distance between the plane $=\begin{v...
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answered Apr 24, 2020
Given : $x^2+2x+3=0---(1) $ and$\qquad ax^2+bx+c =0 ---(2)$It is clear that equation (1) has imagina...
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answered Apr 24, 2020
$|z|=1, \; arg(z)= \theta \qquad z= e^{i \theta}$$\overline{z} =\frac{1}{z} \qquad arg \begin{pmatri...
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answered Apr 24, 2020
https://clay6.com/mpaimg/1855_a.jpg$\overrightarrow{AB}+\overrightarrow{BC}+\overrightarrow{CA}=\ove...
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answered Apr 24, 2020
$n(A)=2; \;n(B)=4$$n(A \times B)=8$$\therefore 8C_3 +8C_4+...8C_8=2^8 -8C_0 -8C_1-8C_2$$\qquad \qqua...
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answered Apr 24, 2020
If the lines are coplanar then, $\begin{vmatrix}x_2-x_1 & y_2-y_1 & z_2-z_1 \\ l_1 & m_1...
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answered Apr 24, 2020
https://clay6.com/mpaimg/1854_a.jpg Given : $y = \sec(\tan^{-1}x)$Let $\tan^{-1} x = \theta$$\implie...
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answered Apr 24, 2020
$(k+1)x+8y=4k$$kx+(k+3)y=3k-1$ has no solution$\therefore \large\frac{k+1}{k} = \frac{8}{k+3} \neq \...
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answered Apr 24, 2020
$|P|=1(12-12)-\alpha(4-6)+3(4-6)$$\qquad = 2 \alpha - 6$$\therefore |P|=|A|^2 = 16$$\implies \alpha ...
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answered Apr 24, 2020
$T_{n+1} - T_n =10$$T_n = nC_3$ and $T_{n+1} = n+1C_3$$\therefore T_{n+1} - T_n = n+1C_3 - nC_3$$\qq...
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answered Apr 24, 2020
This can be written as$\displaystyle\lim_{x\to 0}\frac{(1-\cos 2x)}{x^2}. \frac{(3+\cos x)}{1} . \fr...
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answered Apr 24, 2020
$f(x)=2x^3+3x+k$$f'(x)=6x^2+3 >0 \;\;\forall \;x \in R$$\implies f(x)$ is a strictly increasing f...
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answered Apr 24, 2020
$\large\frac{\tan A}{1 - \frac{1}{\tan A}} + \frac{\frac{1}{\tan A}}{1 - \tan A} $ $= \large\frac{\t...
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answered Apr 24, 2020
https://clay6.com/mpaimg/1853_a.jpgGiven : $y=\sqrt{x}$$2y-x+3=0$To find the point of intersection, ...
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answered Apr 23, 2020
Statement-II : $(p \to q) \leftrightarrow ( \sim q \to \sim p)$$\qquad \qquad \qquad (p \to q) \lef...
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answered Apr 23, 2020
${\large\frac{7}{10} + \frac{77}{100} + \frac{777}{1000}+...} 20 \;terms$$=7 \begin{bmatrix}{ \large...
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answered Apr 21, 2020
${\large\frac{dy}{dx}}=|x|=2$$\implies x = \pm 2$$\therefore y = \displaystyle \int_0^{\pm 2} |t| dt...
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answered Apr 21, 2020
https://clay6.com/mpaimg/1852_a.jpgThe $x$ coordinate of the incentre$=\large\frac{2 \times 0 + 2\sq...
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answered Apr 21, 2020
Given :$\large\frac{x^2}{16}+\frac{y^2}{9} = 1$Having centre $(0,3)$$\implies a = 4, \; b=3$$\theref...
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answered Apr 21, 2020
Given : $\displaystyle\int f(x) dx = \Psi(x)$$I = \displaystyle \int x^5 f(x^3)dx$Put $x^3 = t$$3x^2...
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answered Apr 21, 2020
Given : $x, y, z$ are in $A.P$$\implies 2y = x+z$$\implies 2 \tan^{-1}y = \tan^{-1}x + \tan^{-1}z$$\...
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answered Apr 21, 2020
https://clay6.com/mpaimg/1851_a.jpgLet $B (0,1)$ be any point on the given line.$\therefore B'$ is $...
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answered Apr 20, 2020
https://clay6.com/mpaimg/1850_a.jpg$\qquad$ Let $AB=x$$\qquad \tan (\pi-(\theta +\alpha))=\large\fra...
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