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Answers posted by syedataj761
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A magnet of length $10\; cm$ and magnetic moment $1\; Am^2$ is placed along side AB of an equilateral triangle ABC. If the length of the side AB is $10\; cm$. The magnetic induction at the point 'C' is :
$(\mu_0 = 4 \pi \times 10^{-7} Hm^{-1})$
answered
Jul 8, 2019
D) The magnetic induction at the third vertex C is 10^-4 T.
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