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Answers posted by thanvigandhi_1

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answered Feb 18, 2013
Toolbox:Principal interval of cos is $([o,\pi])$$(cos(2n\pi+x)=cosx) for \;all (n\in\:N)$Ans: $( \la...
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answered Feb 18, 2013
Toolbox: \(sin^{-1}x+cos^{-1}x=\large\frac{\pi}{2}\) \(cos\large\frac{\pi}{2}=0\) ...
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answered Feb 18, 2013
Toolbox: \(sin^{-1}x+cos^{-1}x=\large\frac{\pi}{2}\) for all x \( tan\large\frac{\pi...
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answered Feb 18, 2013
Toolbox: Put \( x=tan\theta \rightarrow \theta = tan^{-1}x\) \(\large\frac{2tan\thet...
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answered Feb 18, 2013
Toolbox: Principal interval of cot is \((0,\pi)\) \(cot(\pi-\theta)=-cot\theta\) ...
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answered Feb 18, 2013
Ans - TrueBy fixing proper domain we can get inverse for all trignometric function.
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answered Feb 18, 2013
Ans - FalseBecause if \( x=cos\: A\: then \: A=cos^{-1}x\)
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answered Feb 18, 2013
Ans - True   By choosing the proper interval with the same span as that of its correspon...
-1 votes
answered Feb 18, 2013
The answer is true   This is the definition of principal value of inverse trignome...
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answered Feb 18, 2013
The answer is true Because,if (a.b) is a point on any graph of a trignometric function then...
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answered Feb 18, 2013
Toolbox:$\tan\large\frac{\pi}{4}=1$if $x>\large\frac{\pi}{4}$, then $\tan x >1$The value of $\...
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answered Feb 18, 2013
Toolbox:$\sin\large\frac{\pi}{6}=\large\frac{1}{2}$$\cos\large\frac{\pi}{6}=\large\frac{\sqrt3}{2}$$...
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