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Answers posted by yamini.v

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answered Jun 7, 2014
Answer : $3.09 \times 10^{22}$Explanation :No of atoms per unit $=8 \times \large\frac{1}{8}+\norma...
0 votes
answered Jun 7, 2014
Answer : $\;AB_{3}$Explanation :As 'A' atom are present at the 8 corners of the cube therefore no o...
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answered Apr 22, 2014
Answer : https://clay6.com/mpaimg/5_figure1.PNGExplanation :$U = nC_{V}T$As T increases U also incr...
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answered Apr 22, 2014
Answer : $\;C_{p}+C_{v}\;$ is larger for a diatomic gas than a monoatomic gas.Explanation :$C_{v} ...
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answered Apr 19, 2014
Answer : $\;infinitely \;many $Explanation :$\;z^{2}+|z|^{2} =0\; ,z \neq 0$$x^{2}-y^{2} + 2 i xy +...
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answered Apr 19, 2014
Answer : $\;\large\frac{\pi}{10}$Explanation :We have , $\; sin \large\frac{\pi}{5} + i\; \normal...
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answered Apr 19, 2014
Answer : straight lineExplanation :$\;|z+1-i|=|z-1+i|\;$$|z-(-1+i)|=|z-(1-i)|$PA=PA , where A denote...
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answered Apr 19, 2014
Answer : $\;\large\frac{|z|^{2}}{2}$Explanation :Let $\;z=x+iy\;.$ Then $\;-iz=y-ix$.Therefore , ...
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answered Apr 18, 2014
Answer : Circle with centre (-1,0) and radius 1Explanation :$|z+1| =1$$|(x+1)+iy| =1$$(x+1)^{2} + ...
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answered Apr 18, 2014
Answer : Can not be evaluatedExplanation :$1+i+i^{2}+i^{3} + i^{4}+i^{5}+i^{6}---+i^{2n}\; =1-1+1-1-...
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answered Apr 18, 2014
Answer : -2 , 2Explanation :Sum of roots $\; \large\frac{-a}{1} = (1-i)+(1+i)$$a=-2$(Since non rea...
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answered Apr 18, 2014
Answer : Straight lineExplanation :Let $\; z=x+iy$Then , $\;z-2-3i\; = (x-2)+i(y-3)$ Let $\;\theta\...
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answered Apr 18, 2014
Answer : $\; cos \large\frac{\pi}{2} - i sin \large\frac{\pi}{2}$Explanation :$\;z=(i^{25})^{3} \; ...
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answered Apr 18, 2014
Answer : $\;-\large\frac{\pi}{4}$Explanation :Let $\;\theta\;$ be the principle value of amplitude...
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answered Apr 18, 2014
Answer : $\;0 + \large\frac{3}{2} i$Explanation :Let $\; z= \large\frac{\sqrt{5+12 i } +\sqrt{5-1...
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answered Apr 18, 2014
Answer : $\;(\large\frac{3+ \sqrt{3}}{4})+(\large\frac{3- \sqrt{3}}{4})i$Explanation :$\large\frac{...
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answered Apr 18, 2014
Answer : $\;\large\frac{3}{16} - \large\frac{\sqrt{7}}{16} i$Explanation :Reciprocal of $\;z = \l...
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answered Apr 18, 2014
Answer : 2Explanation :n=2 , because $\; (1+i)^{2n} = (1-i)^{2n}$$(\large\frac{1+i}{1-i})^{2n} =1$...
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answered Apr 18, 2014
Answer : $\;i$Explanation :$\; \large\frac{i^{4n+1} - i^{4n-1}}{2}\; = \large\frac{i^{4n} . i - i^{...
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answered Apr 18, 2014
Answer : TrueExplanation :True , because $\;i^{n} + i^{n+1} + i^{n+2} + i^{n+3} \;$ $= i^{n}(1 +...
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answered Apr 18, 2014
Answer : FalseExplanation :False , because if $\;z_{1} , z_{2}\;$ and $\;z_{3}\;$ are in A.P. th...
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answered Apr 18, 2014
Answer : FalseExplanation :False , because $\;|x+iy+1| < |x+iy-1|\;$$|(x+1)^{2} + y^{2}| < ...
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answered Apr 18, 2014
Answer : TrueExplanation :True , because $\;arg(z)=arg(1+ i\sqrt{3})+ arg(1+i) +arg(cos \theta + i...
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answered Apr 18, 2014
Answer : FalseExplanation : False , because $\;x+iy=x-iy\;$ => $\;y=0\;$ => number lies on ...
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answered Apr 18, 2014
Answer : FalseExplanation :False , because $\;cos \theta + i sin \theta =0\;$ => $\;cos \theta...
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answered Apr 18, 2014
Answer : TrueExplanation :Let $\;z=2+3i\;$ be a complex number represented by OP . then $\;iz=-3+2i...
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answered Apr 18, 2014
Answer : $\;x^{2}+y^{2} $Explanation :Given that , $\;(2+i)(2+2i)(2+3i)....(2+ni)=x+iy\;$---(1)$\o...
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answered Apr 18, 2014
Answer : Second quadrantExplanation :Conjugate of a complex number is the image of the complex num...
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answered Apr 17, 2014
Answer : iExplanation :$ \large\frac{1-i}{1+i} = \large\frac{1-i}{1+i} \times \large\frac{1-i}{1-i}...
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answered Apr 17, 2014
Answer : $\;-i$Explanation :$\;(-\sqrt{-1})^{4n-3}\; = (-i)^{4n-3} = (-i)^{4n} \; . (-i)^{-3}$...
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answered Apr 17, 2014
Answer : $\;\sqrt{3} x$Explanation :Let $\;z=x+iy\;$ then its polar form is $\;z=r(cos \theta + i s...
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answered Apr 17, 2014
Answer : $\;\sqrt{2}(1+i)$Explanation :$z=|z| (cos \large\frac{\pi}{4} + i sin\large\frac{\pi}{4})$...
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answered Apr 17, 2014
Answer : $-\;2$Explanation :$\;3i^{3}-2ai^{2}+(1-a)i+5\; =-3i+2a+5+(1-a)i $$=2a+5+i(-a-2)\;$, which...
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answered Apr 17, 2014
Answer : 2Explanation :Let $\;z=x+iy\;,z_{1}=x_{1}+iy_{1}\;$ and $\;z_{2} = x_{2}+iy_{2}$Then , $\;...
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answered Apr 17, 2014
Answer : 1Explanation :L.H.S = $|1-\overline{z_{1}}z_{2}|^{2} - |z_{1} - z_{2}|^{2}$$= (1- \overlin...
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answered Apr 17, 2014
Answer : 1Explanation :Let $\;\alpha \;, \beta\;$ be the roots of the equationTherefore , $\;\alpha...
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answered Apr 17, 2014
Answer : $\;\pm6$Explanation :Let $\;\alpha \;, \beta\;$ be the roots of the equation $\;x^{2}-Px...
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answered Apr 17, 2014
Answer : $\;6$Explanation : $\;x=-2-\sqrt{3} i$$\;x+2=-\sqrt{3} i$ => $\;x^{2} +4x+7=0$$\;2x^{4...
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answered Apr 17, 2014
Answer : $\;x^{2}+y^{2}=9 \;and\;x^{2}+y^{2} =16$Explanation :$|z| < 4 \; => \; x^{2}+y^{2...
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answered Apr 17, 2014
Answer : $\;6\;and\;0$Explanation :Distance of the point representing z from the centre of the circ...
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answered Apr 17, 2014
Answer : $\;0$Explanation :Let $\;z_{1}= r_{1}(cos \theta_{1} + i sin \theta_{1}) \;$ and $\;z_{2}...
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answered Apr 17, 2014
Answer : $\;\large\frac{3 \pi}{4}$Explanation :Given that , $\;\overline{z_{1} }+i \overline{z_{2...
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answered Apr 17, 2014
Answer : z lies on imaginary axisExplanation :Let $\;z=x+iy$Then , $\;|z^{2}-1| = |z|^{2}+1\;$$|...
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answered Apr 17, 2014
Answer : $\;x+2y-2=0$Explanation :Let $\; z=x+iy\;$ Then , $\;\large\frac{2z+1}{iz+1}\;= \large\f...
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answered Apr 17, 2014
Answer : $\;-\large\frac{1}{2} \pm \large\frac{\sqrt{3}}{2}$Explanation : $\;z^{2} = \overline{z}\;...
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answered Apr 17, 2014
Answer : $\;-2(a^{2}+b^{2})$Explanation :$\;(x+iy)^{\large\frac{1}{3}}= a+ib\;$$\;(x+iy)^{\large\fr...
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answered Apr 17, 2014
Answer : $\;-2-10i$Explanation :$\; (1+i)^{6} = ((1+i)^{2})^{3}$$= (1^{2} + i^{2} + 2i )^{3}$$= (...
0 votes
answered Apr 16, 2014
Answer : $\;\sqrt{2} (cos \large\frac{5 \pi}{12} + i sin \large\frac{5 \pi}{12})$Explanation :We ha...
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