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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane
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At a height 0.4 m from the ground the velocity of particle projected in angle θ is ˆv=(6i+2j)m/s The angle of projection θ is (g=10m/s2)

(a)45(b)30(c)60(d)tan134

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