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JEEMAIN and NEET
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Physics
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Class11
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Motion in a Plane
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Q)
At a height 0.4 m from the ground the velocity of particle projected in angle $\theta$ is $\hat v=(6 i+ 2 j)m/s$ The angle of projection $\theta$ is $(g=10 m/s^2)$
\[(a)\;45 ^{\circ}\quad (b)\;30 ^{\circ} \quad (c)\;60^{\circ} \quad (d)\tan ^{-1} \frac{3}{4}\]
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