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JEEMAIN and NEET
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Physics
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Class11
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Motion in a Plane
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A projectile is given an initial velocity of $\hat i+2 \hat j$. The cartesian equation of its path is $(g=10 m/s^2)$. ($\hat i$ vector along horizontal $\hat j$ vector along vertically upward)
\[(a)\;y=2x-5x^2 \quad (b)\;y=x-5x^2 \quad (c)\;4y=2x-5x^2\quad (d)\;y=2x-25 x^2\]
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