Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion
Answer
Comment
Share
Q)

A pendulum is released from θ0=60. The rate of change of speed of bob at θ=30 is (g=10m/s2)

(a)53m/s2(b)5m/s2(c)10m/s2(d)2.5m/s2

Home Ask Tuition Questions
Your payment for is successful.
Continue
...