According to hardy Schultze law the order of coagulation power of cations will be :

Question

( A ) $Al^{+3} > {Na^{+}} > Ba^{+2}$
( B ) $Ba^{+2 } > {Al^{+3}} > {Na^{+}}$
( C ) ${Na^{+}} > Ba^{+2} > {Al^{+3}}$
( D ) ${Al^{3+}}>{Ba^{2+}}>{Na^{+}}$