Consider: $CH_{4(g)} + 2O_{2 (g)} \to CO_{2 (g)} + 2H_2O_{ (g)}$ Determine what was oxidized and what was reduced.

Question

$\begin{array}{1 1} \text{(a) C-reduced , O – Oxidised} \\ \text{ (b) H – Reduced , O – Oxidised} \\ \text{ (c) O - reduced , C – Oxidised} \\ \text{ (d) O-reduced , H – Oxidised } \end{array}$