$H_2S$ acts only as a reducing agent while $SO_2$ can act both as a reducing and oxidizing agent because

Question

$\begin{array}{1 1} \text{(a) S in $H_2S$ has - 2 oxidation state} \\ \text{(b) S in $ SO_2$ has oxidation state + 4} \\ \text{ (c) Hydrogen in $H_2S$ more +ve than oxygen} \\ \text{ (d) Oxygen is more - ve in $SO_2$} \end{array}$