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Questions  >>  CBSE XII  >>  Math  >>  Integrals
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Integrate the function $\sqrt{x^2+3x}$

$\begin{array}{1 1} \frac{(2x+3)(\sqrt{x^2+3x}) }{4}+\frac{9}{8} \log \mid \frac{2x+3}{2}+\sqrt{x^2+3x} \mid+c \\ \frac{(2x+3)(\sqrt{x^2+3x}) }{4}- \frac{7}{8} \log \mid \frac{2x+3}{4}+\sqrt{x^2+3x} \mid+c \\ \frac{(2x+3)(\sqrt{x^2+3x}) }{4}+\frac{7}{8} \log \mid \frac{2x+3}{4}+\sqrt{x^2-3x} \mid+c \\ \frac{(x+2)(\sqrt{x^2+3x}) }{2}-\frac{9}{8} \log \mid \frac{2x+3}{2}+\sqrt{x^2+3x} \mid+c \end{array} $

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