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Calculate the number of molecules present in 34.20 grams of cane sugar $(C_{12}H_{22}O_{11})$

$\begin{array}{1 1} (a)\; 6.022 \times 10^{22}\; molecules \\(b)\; 6.022 \times 10^{24}\;molecules\\ (c)\;6.022 \times 10^{20}\; molecules \\ (d)\;6.022 \times 10^{10}\; molecules \end{array} $

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