Simplify the expression : $\large\frac{6+\sqrt 8 i}{3- \sqrt 2 i}$

Question

$\begin{array}{1 1} (a)\;\large\frac{14+12 \sqrt 2 i}{11} \\ (b)\;\large\frac{14-12 \sqrt 2 i}{11} \\ (c)\;\large\frac{12+14 \sqrt 2 i}{11} \\ (d)\;\large\frac{12-14 \sqrt 2 i}{11}\end{array}$