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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2001
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Q)

Two springs A and B having spring constant $K_A$ and $K_B$ . ($K_A= 2K_B$ ) are stretched by applying force of equal magnitude. If energy stored in spring A is E then energy stored in B will be : -


( A ) $\frac{E}{4}$
( B ) $\frac{E}{2}$
( C ) 2E
( D ) 4E

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