For the reaction $2N_2O_5 \to 4NO_2 + O_2$ rate and rate constant are $1.02 \times 10^{–4}$ and $3.4 \times 10^{–5} sec^{–1}$ respectively.Then concentration of $N_2O_5 $ at that time will be : -

Question

( A ) 3
( B ) 1.732
( C ) $3.4 \times 10^{5}$
( D ) $1.02 \times 10^{-4}$