Specific volume of cylindrical virus particle is $6.02 \times 10^{–2} cc/gm$. Whose radius and length are 7 Å & 10Å respectively. If $N_A = 6.02 \times 10^{23}$. Find mol. wt. of virus : -

Question

( A ) $3.08 \times 10^4 kg/mol$
( B ) $3.08 \times 10^3 kg/mol$
( C ) $1.54 \times 10^4 kg/mol$
( D ) $1.54 kg/mol$