Find the area of the region lying in the first quadrant and bounded by $y = 4x^2, x = 0, y = 1$ and $y = 4$.

Question

$\begin{array}{1 1} \frac{7}{3} \;sq.units \\ \frac{5}{3} \;sq.units \\ \frac{11}{3}\;sq.units \\ \frac{10}{3}\;sq.units \end{array} $