Consider two rods of same length and different specific heats ($S_1$, $S_2$), conductivities ($K_1$, $K_2$) a area of cross-sections ($A_1$, $A_2$) and both having temperature $T_1$ and $T_2$ at their ends. If rate of lo of heat due to conduction is equal, then :-

Question

( A ) $K_2A_1=K_1A_2$
( B ) $\frac{K_1A_1}{S_1}=\frac{K_2A_2}{S_2}$
( C ) $\frac{K_2A_1}{S_2}=\frac{K_1A_2}{S_1}$
( D ) $K_1A_1=K_2A_2$