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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2002
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Q)

A wave travelling in positive X-direction with A = 0.2 m velocity = 360 m/s and $\lambda$ = 60 m, then correct expression for the wave is : -


( A ) $y=0.2sin[\pi(6t+\frac{X}{60})]$
( B ) $y=0.2sin[\pi(6t-\frac{X}{60})]$
( C ) $y=0.2sin[2\pi(6t+\frac{X}{60})]$
( D ) $y=0.2sin[2\pi(6t-\frac{X}{60})]$

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