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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2002
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Q)

Displacement between max. P.E. position and max. K.E. position for a particle excuting simple harmonic motion is : -


( A ) $+a$
( B ) $\pm a$
( C ) $\pm \frac{a}{2}$
( D ) – 1

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