Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2002
Answer
Comment
Share
Q)

In Hydrogen atom, energy of first excited state is – 3.4 eV. Then find out KE of same orbit of Hydrogen atom : -


( A ) – 13.6 eV
( B ) + 13.6 eV
( C ) + 6.8 eV
( D ) + 3.4 eV

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...