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JEEMAIN and NEET
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2002
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Q)
In Hydrogen atom, energy of first excited state is – 3.4 eV. Then find out KE of same orbit of Hydrogen atom : -
( A ) – 13.6 eV
( B ) + 13.6 eV
( C ) + 6.8 eV
( D ) + 3.4 eV
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