$3A\rightarrow 2B$, rate of reaction $\frac{+d[B]}{dt}$ is equals to : -

Question

( A ) $-\frac{3}{2}\frac{d[A]}{dt}$
( B ) $-\frac{1}{3}\frac{d[A]}{dt}$
( C ) $-\frac{2}{3}\frac{d[A]}{dt}$
( D ) $+2\frac{d[A]}{dt}$