The solubility product of AgI at $25^oC$ is $1.0 \times 10^{–16} mol^2 L^{–2}$. The solubility of AgI in $10^{–4} N$ solution of KI at $25^oC$ is approximately (in $mol\; L^{–1}$) :

Question

( A ) $1.0 \times 10^{-16}$
( B ) $1.0 \times 10^{-12}$
( C ) $1.0 \times 10^{-10}$
( D ) $1.0 \times 10^{-18}$