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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2003
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Q)

The linkage map of X-chromosome of fruitfly has 66 units, with yellow body gene (y) at one end and bobbed hair (b) gene at the other end. The recombination frequency between these two genes (y and b) should be : -


( A ) > 50%
( B ) 60%
( C ) 100%
( D ) $\leq $ 50

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