The phase difference between two waves, <br> $y_{1}=10^{-6} \sin \{100t+(x/50)+0.5\}m$ <br> $y_2=10^{-6} \cos \{100t+(\frac{ x} {50})\}m$ <br> Where X is expressed in metres and t is expressed in seconds, is approximately : -

Question

( A ) 1.5 radians
( B ) 1.07 radians
( C ) 2.07 radians
( D ) 0.5 radians