In the reaction$^{2}_{1}H + ^{3}_{1}H\rightarrow^{4}_{2}He +^{1}_{0}n$. If the binding energies of$^{2}_{1}H$ ,$^{3}_{1}H$ and $^{4}_{2}He$ are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is

Question

( A ) a + b + c
( B ) c – a – b
( C ) c + a – b
( D ) a + b – c