The equation $\large\frac{1}{4}$$(4x^2-8x-p)=132$, is satisfied. When $x=+8$ and $x=-6$. What is the value of $\large\frac{p}{4}$ ?

Question

$\begin{array}{1 1} (a)\;84 \\ (b)\;-84 \\ (c)\;42\\(d)\;-42 \end{array}$