A uniform rod AB of length $l$ and mass $m$ is free to rotate about point $A$. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about $A$ is $\frac{ml^2}{3}$,the initial angular acceleration of the rod will be <br> <img src =" "/>

Question

( A ) $\frac{3g}{2l}$
( B ) $\frac{2g}{3l}$
( C ) $\frac{3}{2} gl$
( D ) $mg \frac{l}{2}$