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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2007
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If NaCl is doped with 104 mole % of SrCl2, the concentrate of cation vacancies will be : (NA=6.02×1023)mol1


( A ) 6.02×1014mol1
( B ) 6.02×1016mol1
( C ) 6.02×1015mol1
( D ) 6.02×1017mol1
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