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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2008
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If M (A, Z), $M_p$ and $M_n$ denote the masses of the nucleus $^{A}_ {Z} X$ , proton and neutron respectively in units of u (1u = 931.5 Me$\frac{V}{C}^2$ ) and BE represents its bonding energy in MeV, then -


( A ) $M(A,Z)=ZM_p+(A-Z)M_n+\frac{BE}{c}^2$
( B ) $M(A,Z)=ZM_p+(A-Z)M_n-\frac{BE}{c}^2$
( C ) $M(A, Z) = ZM_p + (A – Z) M_n + BE$
( D ) $M(A, Z) = ZM_p + (A – Z) M_n – BE$

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