Given :<br> (i) $cu^{2+}+2e^{-}\to Cu,E^{\circ}=0.337 V$ <br> (i) $cu^{2+}+e^{-}\to Cu,E^{\circ}=0.153V$ <br> Electrode potential Eº for the reaction,$ Cu^{+} + e^{–}\rightarrow Cu$ will be :

Question

( A ) 0.30 V
( B ) 0.52 V
( C ) 0.90 V
( D ) 0.38 V