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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2009
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Q)

Given :<br> (i) $cu^{2+}+2e^{-}\to Cu,E^{\circ}=0.337 V$ <br> (i) $cu^{2+}+e^{-}\to Cu,E^{\circ}=0.153V$ <br> Electrode potential Eº for the reaction,$ Cu^{+} + e^{–}\rightarrow Cu$ will be :


( A ) 0.30 V
( B ) 0.52 V
( C ) 0.90 V
( D ) 0.38 V

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