An alpha nucleus of energy $\frac{1}{2} mv^2$ bombards a 2 heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to –

Question

( A ) $V^2$
( B ) $\frac{1}{V^4}$
( C ) $\frac{1}{Ze}$
( D ) $\frac{1}{m}$