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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2010
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Q)

A source S1 is producing, 1015 photons per second of wavelength 5000 Å. Another source S2 is producing 1.02 × 1015 photons per second of wavelength 5100 Å. Then, (power of S2)/(power of S1) is equal to –


( A ) 1.04
( B ) 1
( C ) 0.98
( D ) 1.02
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