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JEEMAIN and NEET
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NEET PAST PAPERS
>>
2010
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Q)
A source
S
1
is producing,
10
15
photons per second of wavelength 5000 Å. Another source
S
2
is producing 1.02 ×
10
15
photons per second of wavelength 5100 Å. Then, (power of
S
2
)/(power of
S
1
) is equal to –
( A ) 1.04
( B ) 1
( C ) 0.98
( D ) 1.02
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