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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2012
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The potential energy of a particle in a force field is :$U=\frac{A}{r^2}-\frac{B}{r}$ where A and B are positive constants and r is the distance of particle from the centre of the field. For stable equilibrium, the distance of the particle is


( A ) $\frac{A}{B}$
( B ) $2\frac{A}{B}$
( C ) $\frac{B}{A}$
( D ) $\frac{B}{2}A$

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