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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2012
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Q)

A ring is made of a wire having a resistance $R_0 = 12\Omega$ . Find the points A and B, as shown in the figure, at which a current carrying conductor should be connected so that the resistance R of the sub circuit between these points is equal to $\frac{8}{3}\Omega$ : <br>



( A ) $\frac{l_1}{l_2}=\frac{1}{3}$
( B ) $\frac{l_1}{l_2}=\frac{1}{2}$
( C ) $\frac{l_1}{l_2}=\frac{3}{8}$
( D ) $\frac{l_1}{l_2}=\frac{5}{8}$

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