Steam at $100^0 \;C$ is passed into 20g of water at $10^0 \;C$ When water acquires a temperature of $80^0 \;C$, the mass of water present will be: <br> [Take specific heat of water = $1 \; cal\; g^{-10} C^{-1}$ and latent heat of steam = $540 \;cal \;g^{–1}$]

Question

( A ) 24 g
( B ) 22.5 g
( C ) 42.5 g
( D ) 31.5 g