Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2014
Answer
Comment
Share
Q)

A thin semicircular conducting the ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. Teh potential difference developed across the ring when its speed is v, is:<br>

image

( A ) $2rBv$ and $R$ is at higher potential
( B ) $\pi rBv$ and $R$ is at higher potential
( C ) $2rBv$ and $R$ is at higher potential
( D ) $Bv \pi r^2/2$ and $P$ is at higher potential

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...