When 22.4 litres of $H_2(g) $ is mixed with 11.2 litres of $Cl_2 (g)$, each at STP, the moles of $HCl(g) $ formed is equal to -

Question

( A ) 1.5 mol of HCl(g)
( B ) 1 mol of HCl(g)
( C ) 0.5 mol of HCl(g)
( D ) 2 mol of HCl(g)