In the correct <br> $X - C \equiv CH \xrightarrow[\text{(2) $CH_3CH_2Br$}]{\text{(1) $NaNH_2 / liq. NH_3$}} X \xrightarrow[\text{(2) $CH_3CH_2Br$}]{\text{$(1) NaNH_2 / liq.NH_3$}}$ <br> X and Y are:

Question

( A ) X = 2-Butyne ; y=2-Hexyne
( B ) X = 1-Butyne; y = 2-Hexyne
( C ) X = 1 - Butyne; Y = 3 - Hexyane
( D ) X = 2-Butyne ; Y=3-Hexyne