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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2016
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Q)

Given the value of Rydberg constant is $10^7 \;m^{-1}$, the wave number of the last line of the Balmer series in hydrogen spectrum will be :


( A ) $0.25 \times 10^7 \;m^{–1}$
( B ) $0.5 \times 10^7 \;m^{–1}$
( C ) $0.025 \times 10^4 \;m^{–1}$
( D ) $2.5 \times 10^7 \;m^{–1}$

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