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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2016
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Q)

If the velocity of a particle is v =$At + Bt^2$, where $A$ and $B$ are constants, then the distance travelled by it between 1s and 2s is :


( A ) $3A+7B$
( B ) $\frac{A}{2} + \frac{B}{3}$
( C ) $\frac{3}{2} A + \frac{7}{3}B$
( D ) $\frac{3}{2} A + 4B$

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