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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2017
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In the electrochemical cell - <br> Zn|ZnSO4(0.01M)||CuSO4(1.0M)|Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 0.1M and that of CuSO4 changed to 0.01M, the emf changes to E2. From the followings, which one is the relayionship between E1 and E2 ? (Given , RTF=0.059)


( A ) E1=E2
( B ) E1<E2
( C ) E1>E2
( D ) E2=0E1
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